1.

In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log y axis was found to be `0.301` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `3.0` atm.

Answer» Correct Answer - 6
`log((x)/(m))=logK+(1)/(n)logP`
`therefore`plot of `log((x)/(m))` versus log P is linear with slope `=(1)/(6)` and intercept `=log " "K`
Thus `(1)/(n)=tantheta=tan45^(@)=1" or "n=1`
`log" "K=0.301" or "K="antilog "0.301=2`
At `P=3` atm
`(x)/(m)=KP^(1//n)=2xx(3)^(1)=6`


Discussion

No Comment Found