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In an adsorption experiment, a graph between log `(x/m)` versus log `P` was found to be linear with a slope of `45^(@)` . The intercept on the log y axis was found to be `0.301` . Calculate the amount of the gas adsorbed per gram of charcoal under a pressure of `3.0` atm. |
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Answer» Correct Answer - 6 `log((x)/(m))=logK+(1)/(n)logP` `therefore`plot of `log((x)/(m))` versus log P is linear with slope `=(1)/(6)` and intercept `=log " "K` Thus `(1)/(n)=tantheta=tan45^(@)=1" or "n=1` `log" "K=0.301" or "K="antilog "0.301=2` At `P=3` atm `(x)/(m)=KP^(1//n)=2xx(3)^(1)=6` |
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