Saved Bookmarks
| 1. |
In an APa3 Men a s, d-3, an so tind n and sp |
|
Answer» We have, a= 5, d=3 and an=50 > a+(n-1)d= 50 > 5+(n-1)3=50 > 3(n-1)=50-5 > n-1 = 45/3 > n-1 = 15+1 = 16 Putting n = 16, a= 5 and l = an = 50 in Sn= n/2(a+l),We get S16 = 16/2( 5 + 50) = 8 × 55 = 440 Hence, n= 16 and S16 = 440 Like my answer if you find it useful! |
|