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In an arithmetic sequence having terms natural numbers, prove that if one of the terms is a perfect square, it will have more that this as the perfect square term. |
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Answer» As we know when a definite number of common difference of an arithmetic sequence is added to a term we get another term of the same sequence. If n2 is a perfect square term, add (2n + d) times d to n2. n2 + (2n + d) x d = (n + d)2. This is nothing but a perfect square term. |
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