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In an astronomical telescope, the focal length of the objective lens is 100 cm and of eye-piece is 2 cm . The magnifying power of the telescope for the normal eye isA. 50B. 10C. 100D. `(1)/(50)` |
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Answer» Correct Answer - A Magnification of astronomical telescope for normal eye is, `m=(f_(o))/(f_(e ))=-(100)/(2)=-50` |
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