In an atom, the total number of electron having quantum number, n = 4(

1.	In an atom, the total number of electron having quantum number, n = 4(m_(1)) =1 and m_(s) = -1//2 is
Answer» Solution :When `n = 4, L = 0, 1, 2, 3` When `l = 0, m = 0` When `l = 1, m = -1, 0, + 1` (Two p-orbitals have `\|m\| = 1`) When `l = 1, m = -2, -1, 0 + 1, +2` (Two d-orbitals have `\|m\| = 1`) when `l = 3, m = -3,-2,-1, 0 , + 1, + 2, +3` (Two f-orbitals have `\|m\| =1`) Thus, `\|m_(1)\| =1` for two p, two d and two f-orbitals. Each of these orbitals has only one electron with `m_(s) = - (1)/(2)`. HENCE, total number of ELECTRONS = 6

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