In an atom with 2K, 6L, 1M and 2N eletrons the number of electrons wit

1.	In an atom with 2K, 6L, 1M and 2N eletrons the number of electrons with m = 0, s = +(1)/(2) are
Answer» 2 7 8 16 Solution :Each subshell i.e., s, p, d, f have an orbital for which m = 0. Thus, for the above CONFIGURATION, `(1s^(2))/(K), (2s^(2)2p^(6))/(L), (3s^(2)3p^(3)3d^(3))/(M), (4s)/(N)` The no. of electrons for which m = 0 is `s = + (1)/(2)` equal to = 1+1+1+1+1+1+1 = 7.

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