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In an electric circuit, two resistors are connected in series to a 6V battery. Find the heat dissipated by the 4 ohm resistor in 5s. ​

Answer»

tion:EQUIVALENT resistance of the circuit is R = 4+2 = 6Ω.Voltage of cell, V = 6 VTime taken = t = 5 sTotal resistance of the circuit = R = R1 + R2 = 2 + 4 = 6 ΩCurrent, I = V/R = 6/6 = 1 AHeat dissipated by the 4 Ω resistor in 5 s is GIVEN as,H = I2RtH = 1 × 4 × 5 = 20 J



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