In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will beA. `sqrt((eV)/(m))`B. `sqrt((e)/(Vm))`C. `sqrt((2eV)/(m))`D. none of these

In an electron gun, the electrons are accelerated by the potential `V`

1.	In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will beA. `sqrt((eV)/(m))`B. `sqrt((e)/(Vm))`C. `sqrt((2eV)/(m))`D. none of these
Answer» Correct Answer - C `W=qV" ""i.e. "1/2mv^(2)=qV` `therefore" "v=sqrt((2qV)/m)=sqrt((2eV)/m)" "(thereforeq=e)`

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In an electron gun, the electrons are accelerated by the potential `V`. If the `e` is the charge and `m` is the mass of the electron, then the maximum velocity of these electrons will beA. `sqrt((eV)/(m))`B. `sqrt((e)/(Vm))`C. `sqrt((2eV)/(m))`D. none of these

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