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In an estimation of sulphur by Carius method, 0.468 of an organic sulphur compound gave 0.668 g of barium sulphate. Find the percentage of sulphur in the compound. |
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Answer» SOLUTION :`"PERCENTAGE of sulphur" = (32)/(233) xx ("Mass of barium sulphate")/("Mass of compound") xx 100` `=(32)/(233) xx ((0.668 G))/((0.468 g)) xx 100=19.60%` |
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