1.

In an examination, a student who gets 20% of maximum marks fail by 5 marks. Another student who scores 30% of the maximum marks gets 20 marks more than the pass marks. What is the necessary percentage required for passing ?

Answer»

Let the maximum marks be x. Then,

Pass mark for the 1st student = \(\frac{20}{100}\) x x + 5

Pass mark for the 2nd student = \(\frac{30}{100}\) x x - 20

Since pass marks are same for both the students,\(\frac{20X}{100}\) + 5 = \(\frac{30X}{100}\) - 20

\(\Rightarrow\) \(\frac{10X}{100}\) = 25  \(\Rightarrow\) x = 250

\(\therefore\) Pass mark = \(\frac{20}{100}\) x 250 + 5 = 55

Pass percentage = \(\frac{55}{250}\) x 100 = 22%



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