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In an experiment , 2 moles of HI are taken into an evacuated 10.0 litre container at 720 K. The equilibrium constant equals to 0.0156for the gaseous reaction, `2 HI (g) hArr H_(2) (g) + I_(2)(g).` find equilibrium concentration of ` HI (g) , H_(2) (g) , I_(2)(g).` |
Answer» Correct Answer - `HI = 1.6 " mole " H_(2)= 0.2 " mole " I_(2) = 0.2 " mole "` Suppose x moles of `H_(2)` are formed at eqm. Then concentrations at equilibrium will be : `[HI] = (2-2 x ) //10,[H_(2)] = x // 10 and [I_(2)] = x//10 " mol " L^(-1).` |
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