In an experiment, DNA is treated with a compound which tends to place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases from 0.34 nm to 0.44 nm. Calculate the length of DNA double helix (which has 2 x 109 bp) in the presence of saturating amount of this compound.

In an experiment, DNA is treated with a compound which tends to place

1.	In an experiment, DNA is treated with a compound which tends to place itself amongst the stacks of nitrogenous base pairs. As a result of this, the distance between two consecutive base increases from 0.34 nm to 0.44 nm. Calculate the length of DNA double helix (which has 2 x 109 bp) in the presence of saturating amount of this compound.
Answer» 2 x 10⁹ x 0.44 x 10^-9/bp = 0.88 m.