In an experiment ethyliodide in ether is allowed to stand over magnesium pieces. Magnesium dissolves and product is formed (a) Name the product and write the equation for the reaction. (b) Why all the reagents used in the reaction should be dry? Explain. (c) How is acetone prepared from the product obtained in the experiment?

In an experiment ethyliodide in ether is allowed to stand over magnesi

1.	In an experiment ethyliodide in ether is allowed to stand over magnesium pieces. Magnesium dissolves and product is formed (a) Name the product and write the equation for the reaction. (b) Why all the reagents used in the reaction should be dry? Explain. (c) How is acetone prepared from the product obtained in the experiment?
Answer» Solution :(a) When ethyl IODIDE in ether is allowed to stand over magnesium pieces. the product formed will be Ethyl magnesium iodide. `CH_3 - CH_2l + Mg overset("dry ether")to underset(("Grignard REAGENT"))underset("Ethyl magnesium iodide")(CH_3 - CH_2 MgI)` (b) Grignard reagent are highly reactive compounds and react with any source of proton to give hydrocarbons. EVEN when water is there. it is sufficiently acidic to CONVERT it into the corresponding hydrocarbon. So it is necessary to avoid even traces of moisture with the grignard reagent as they are highly reactive. That is why the all reagents used in the reaction should be dry. (c ) `CH_3 - MgI " to "CH_3 - underset(O)underset(\|\|)C - CH_3` METHYL magnesium iodide reacts with acetyl chloride to form acetone.