1.

In an experiment of simple pendulum, the errors in the measurement of length of the pendulum (L) and time period (T) are 3% and 2% respectively. The maximum percentage errors in the value of L/T^(2) is

Answer»

SOLUTION :Maximum percentage error in the value of`L/T^(2)=((DeltaL)/Lxx100)+2((DELTAT)/Txx100)`
`=3+(2xx2)=3+4=7%`


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