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In an experiment on photoelectric effect, the slope of the cut off voltage versus frequency of incident light is found to be 4.12 × 10-15 Vs. Calculate the value of Planck’s constant. |
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Answer» Given, slope of graph = 4.12 × 10-15 Vs since, slope of graph = \(\frac{h}{e}\) ∴ h = e × slope of graph = 1.6 × 10-19 × 4.12 × 10-15 = 6.59 × 10-34Js |
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