1.

In an experiment on photoelectric effect, the slope of the cut off voltage versus frequency of incident light is found to be 4.12 × 10-15 Vs. Calculate the value of Planck’s constant.

Answer»

Given, slope of graph = 4.12 × 10-15 Vs

since, slope of graph = \(\frac{h}{e}\)

∴ h = e × slope of graph

= 1.6 × 10-19 × 4.12 × 10-15

= 6.59 × 10-34Js



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