InterviewSolution
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InterviewSolution
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In an experiment, the specific heats of some inert gases (at ordinary temperature) are measured. These are shown in the table below.GasAtomic masscal.g-1K-1mHelium4.000.748Neon20.180.147Argon39.940.0760Krypton83.800.0358Xenon131.300.0226Try to discover a regularity in the data and explain it on the basis of kinetic theory. |
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Answer» Let us find the product of atomic mass and specific heat i.e., molar sp. heat from the given data (i) For Helium, M x cv = 4 x 0.748 = 2.99 Cal/K (ii) For Neon, M x cv = 20.18 x 0.147 = 2.97 Cal/K (iii) For Argon, M x cv = 39.94 x 0.076 = 3.04 Cal/K (iv) For Crypton, M x cv = 83.83 x 0.358 = 3.00 Cal/K (v) For Xenon, M x cv = 131.3 x 0.226 = 2.97 Cal/K and 3/2 R = 3/2 x 1.98 = 2.97 Cal/K So, from the above data, it is clear that molar specific heat i.e., product of a atomic mass and specific heat is nearly constant for all the gases and is equal to 3/2 R, in case of all monoatomic gases as given by the kinetic theory of gas |
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