InterviewSolution
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InterviewSolution
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In an experiment, the values of refractive indices of glass were found to be `1.54, 1.53, 1.44, 1.54, 1.56` and `1.45` in successive measurements (i) mean value of refreactive index of glass (ii) mean absolute error (iii) relative error and (iv) percentage error are respectively.A. `1.51,0.04,0.03%, 3%`B. `1.51,0.4,0.03%, 3%`C. `15.1,0.04,0.03%, 3%`D. `1.51,0.4,0.3%, 3%` |
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Answer» Correct Answer - A `mu_("mean") = (sum mu)/(6), Delta u_("mean") = (sum(mu_("mean") - mu))/(6)`, relative `%` error in `mu = (Delta mu_("mean"))/(mu_("mean")) xx 100` |
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