1.

In an experiment to determine the thermal conductivity of copper with Searle's apparatus, 100 gm of water flowed in 4.2 minutes past the cold end of the copper bar, its initial and final temperatures being 25°C and 52°C respectively. If the temperature difference between two points in the bar 10 cm apart is 23°C and the area of cross-section of the bar is 5 "cm"^2,calculate the coefficient of thermal conductivity of copper. Specific heat capacity of water 4,200 "J kg"^(-1) "K"^(-1)

Answer»

SOLUTION :HEAT gained by water `= Q = "m c d T"`
`= 100 XX 10^(-3) xx 4200 xx (52 - 25) = 11340` J
`A = 5 xx 10^(-4) m^(2) , theta_1 - theta_2 = 23^(@) C = 23 "K", d = 0.10 m, t = 4.2 xx 60 = 252 s`,
`K= (Q d)/( A ( theta_1 - theta_2 ) t ) = ( 11340xx 0.10)/( 5 xx 10^(-4) xx 23 xx 252)= 292.3 "Wm"^(-1) "K"^(-1)`


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