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In an experiment to estimate the size of a molecue of oleic acid 1mL of oleic acid is dissolved in 19 mL of alochol. Then 1 mL of this solution is dilluted to 20 mL by adding alcohol. Now 1 drop of this diluted solution is placed on water in a shallow trough. The solution spreads over the surface of water forming one molecule thick layer. Now, lycopodium powder is sprinkled evenly over the film and its diameter is measured. Knowing the volume of the drop and area fo the film we can calculate the thickness of the film which will give us the size of oleic acid molecule. Read the passage cearfully and answer the following questions : (a) why do we dissolve oleic acid in alcohol ? (b) What is the role of lycompodium powder ? (c ) What would be the volume of oleic acid in each mL of solution prepared ? (d) How will you calculate the volume of n drops of this solution of oleic acid ? (e ) What will be the volume of oleic acid in one drop of this solution ? |
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Answer» Solution :(a) Oleic acid is DISSOLVED in alcohol, because it does no dissolve in water. (b) When LYCOPODIUM POWDER is sprinkled evenly, it spreads over the entire surface of water. When a drop of perpared solution is dropped on water, oleic acid does not dissolve in water. Instead, it spreads on the water surface pushing the lycopodium powder away to clear a circular area where the drop falls. We can therefore, measure the area over which oleic acid spreads. (c ) Volume of oleic acid in each mL of solution prepared ` (1)/(20)mLxx(1)/(20) = (1)/(400)mL` (d) Volume of n drops of this solution of oleic acid can be calculated by using a burette and measuring CYLINDER. (e ) If 1 mL of solution contains n drops, then volume of oleic acid in one drop ` = (1)/((400n)) mL` |
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