In an experiment to find the thermal conductivity of rubber, a tube of length 10 cm with external radius 0.5 cm and internal radius 0.3 cm is immersed in 0.28 g of water at 30°C contained in a copper calorimeter of mass 0.20 kg and specific heat capacity 385 "JKg"^(-1) "K"^(-1). Through the tube, steam is passed for 10 minutes and the final maximum temperature of water and calorimeter is 42^(@) C. Calculate the thermal conductivity of rubber. Specific heat capacity of water = 4200 "JKg"^(-1) "K"^(-1).

In an experiment to find the thermal conductivity of rubber, a tube of

1.	In an experiment to find the thermal conductivity of rubber, a tube of length 10 cm with external radius 0.5 cm and internal radius 0.3 cm is immersed in 0.28 g of water at 30°C contained in a copper calorimeter of mass 0.20 kg and specific heat capacity 385 "JKg"^(-1) "K"^(-1). Through the tube, steam is passed for 10 minutes and the final maximum temperature of water and calorimeter is 42^(@) C. Calculate the thermal conductivity of rubber. Specific heat capacity of water = 4200 "JKg"^(-1) "K"^(-1).
Answer» SOLUTION :`K = ((W_1 C_1 div WC ) ( theta_4 - theta_3) )/( t) XX (2.303 xx log_(10) ((r_3)/( r_1 )) )/( 2 pi L [ theta_1 - ((theta_3 div theta_4)/(2) ) ])` `= ((0.20 xx 385 div0.28 xx 4200 ) (42-030))/( 600) xx (2.303 xx log_(10) ((0.5)/( 0.3)) )/( 2 xx 3.14 xx 16 xx 10^(-2) [ 100- 36] )` `=0.199 "Wm"^(-1) "K"^(-1)`