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In an experiment, two capacities measured are `(1.3 +- 0.1)muF` and `(2.4+- 0.2)muF.` Calculate the total capacity in parallel with percentage error. |
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Answer» Here, `C_1 = (1.3 +- 0.1)muF and C_2 = (2.4 +-0.2)muF.` In parallel, `C_p = C+1 +C_2 = 1.3 +2.4 = 3.7muF, Delta C_p = +-(DeltaC_1 + DeltaC_2) = +-(0.1 +0.2_ = +-0.3` `% "age error" =l +- (0.3)/(3.7)xx100 = +- 8.1%` Hence, `C_p = (3.7 +- 0.3)muF = 3.7muF +- 8.1%` |
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