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In an experiment using post-office box, the resistance of a wire is found to be (64 pm 1) ohm. The length and radius of the wire are measured to be (156.0 pm 0.1) cm and (0.26 pm 0.001) cm. Calculate specific resistance (or resistivity) of the material of the given wire, within the limits of percentage error. |
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Answer» Solution :Specific resistance, `rho=(pir^(2)R)/(L)=8.7xx10^(-4)` ohm metre `(DELTA rho)/rhoxx100=[2((Deltar)/r)+(DeltaR)/R+(DELTAL)/l]xx100=2%` |
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