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In an ionic crystalline solid atoms of element Y form hcp lattice. The atoms of element X occupy one third of tetrahedral voids. What is the formula of the compound? |
Answer» In the given hcp lattice, Y atoms are present at 12 corners and 2 face centres. \(\therefore\) Number of Y atoms \(= \frac{1}{2} \times 12 + 2 \times \frac{1}{2} = 3\) There are 6 tetrahedral voids, the number of X atoms \(=\frac{1}{3} \times 6 = 2\) \(\therefore\) Formula of the compound is X2Y3. |
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