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In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å`A. 4B. `2sqrt3`C. `3sqrt3`D. `4/sqrt3` |
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Answer» Correct Answer - A `r_+/r_(-) = 1.6/1.864=0.858` So, It is CsCl type of unit cell So `sqrt3 a=2(r_+ +r_-)` So `a=(2(1.864+1.6))/sqrt3Å=2xx2Å=4Å` |
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