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In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å` |
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Answer» Correct Answer - 4 `(r_(+))/(r_(-)) = (1.6)/(1.864) = 0.858` So, it is CsCl type unit cell So `sqrt3 a = 2 (r_(+) + r_(-))` So `a = (2(1.864 + 1.6))/(sqrt3) Å = 2 xx 2 Å = 4Å` |
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