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In an isobaric process, the ratio of heat supplied to the system (dQ) and work done by the system (dW) for diatomic gas isA. `1 : 1`B. `7 : 2`C. `7 : 5`D. `5 : 7` |
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Answer» Correct Answer - B `-(dQ)/(dW)=(dQ)/(dQ-dE), dE=dW+dQ, -dW=dQ-dE` `=(nc_(p)dT)/(nc_(p)dT-nc_(v)dT)=(c_(p))/((c_(p)-c_(v)))` `=(7R)/(2R){"for diatomic of gas "c_(p)=(7R)/(2)}`. |
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