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In an isosceles triangle ABC, AB = AC = 25 cm, BC = 14 cm. Calculate the altitude from A on BC. |
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Answer» We have, AB = AC = 25cm BC = 14cm In ⊿ ACD and ⊿ ABD ∠ADB =∠ADB = 90 AB = AC = 25cm AD = AD (Common) ⊿ ABD ≅∠ACD ∴BD = CD = 7cm (By c.p.c.t) In ⊿ACD AB2 = AD2 + BD2 252 = AD2 + 72 625 = AD2 + 49 AD2 = 625 - 49 AD2 = 576 AD = \(\sqrt{576}\) AD = 24 cm |
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