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In an isosceles triangle ABC with AB-AC, BD is perpendicular from B to theside AC. Prove that13.BD2 - CD 2CD. AD |
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Answer» Proof: In triangle ABD., AB² = AD² + BD²But BC = ACAC² = AD² + BD²(AD+DC)² =AD² + BD²AB² + DC² + 2AD.DC = AD² + BC²2AD. DC = BD² - DC²BD² - DC² = 2AD.CDhence proved |
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