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In an `NPN` transistor the collector current is `24 mA`. If `80%` of electrons reach collector it base current in `mA` isA. 3B. 6C. 10D. 20 |
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Answer» Correct Answer - B `I_(c)=80/100I_(e)` or `I_(e)=(100I_c)/80=100/80xx24 mA=30 mA` `I_b=I_(e)-I_c=30-24=6 mA` |
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