In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t "in second". Here 1 cm is th end correction. The upper end and the lower end of the tube are respectively :

In an organ pipe ( may be closed or open of 99 cm length standing wave

1.	In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t "in second". Here 1 cm is th end correction. The upper end and the lower end of the tube are respectively :
Answer» OPEN - closed closed - open open - open closed - closed Solution :`(0.1 mm) cos ( 2pi)/(0.8) ( y + 1 cm ) cos 2 pi7 (400) t` end correction is `1 cm`. So at `y = - 1 cm`. `(0.1 mm) cos ( 2 pi)/(0.8) ( - 1 cm + 1 cm) = ( 0.1 mm) cos (0) =` ANTINODE So upper end is open. At lower end `y = 99 cm = 0.99 m` `= (0.1 mm) cos ( 2 pi)/( 0.8) (0.99 + 0.01)` ` = 0.01 cos ( 5 pi)/(2) = 0 rArr` Node So tube is open closed.