In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t in second. Here 1 cm is th end correction. Equation of the standing wave in terms of excess pressure is - (Bulk modulus of air B = 5 xx 10^(5) N//m^(2))

In an organ pipe ( may be closed or open of 99 cm length standing wave

1.	In an organ pipe ( may be closed or open of 99 cm length standing wave is setup , whose equation is given by longitudinal displacement xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos 2 pi (400) t where y is measured from the top of the tube in metres and t in second. Here 1 cm is th end correction. Equation of the standing wave in terms of excess pressure is - (Bulk modulus of air B = 5 xx 10^(5) N//m^(2))
Answer» `P_(ex) = (125 pN//m^(2)) sin ( 2PI)/(0.8) ( y + 1 cm) COS 2 pi (400 t)` `P_(ex) = (125 pN//m^(2)) cos( 2pi)/(0.8) ( y + 1 cm) sin 2 pi (400 t)` `P_(ex) = (225 pN//m^(2)) sin ( 2pi)/(0.8) ( y + 1 cm) cos 2 pi (200 t)` `P_(ex) = (225 pN//m^(2)) cos ( 2pi)/(0.8) ( y + 1 cm) sin 2 pi (200 t)` SOLUTION :`P_(ex) = -B( d xi)/( d x)` `= ( 5 xx 10^(5)) xx (0.1 xx 10^(-3)) ( 2pi)/(0.8) sin ( 2pi)/( 0.8)` `(y + 1 cm) cos2 p(400) t` `= (125 pi N//m^(2)) sin ( 2pi)/(0.8) ( y + 1 cm) cos 2 pi (400 t)`