InterviewSolution
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InterviewSolution
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In an organ pipe (may be closed or open ) of `99 cm` length standing wave is set up , whose equation is given by longitudinal displacement. `xi = (0.1 mm) cos ( 2pi)/(0.8) (y + 1 cm) cos (400) t`where `y` is measured from the top of the tube in `metres` and `t "in" seconds` . Here `1 cm` is the end correction. The upper end and the lower end of the tube are respectively .A. open - closedB. closed - openC. open - openD. closed - closed |
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Answer» Correct Answer - A `xi = (0.1 mm) cos ( 2pi)/( 0.8) ( y + 1 cm) cos (400 t)` End correction is `1 cm` , so at `y = - 1 cm` `xi = (0.1 mm) cos ( 2 pi)/(0.8) ( - 1 cm + 1 cm)` `= (0.1 mm) cos (0) = "Antinode"` So upper end is open . At lower end `y = 99 cm = 0.99 m` `xi = (0.1 mm) cos ( 2pi)/( 0.8) (0.99 + 0.01)` `= 0.01 cos ( 5 pi)/(2) = 0` `rArr` Node So tube is open closed. |
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