In an organic compound, the ratio of masses of C, H and N are 9:1:3.5

In an organic compound, the ratio of masses of C, H and N are 9:1:3.5 and molecular mass is 108. What will be the empirical formula and molecular formula of the compound.

Answer»

Element	Ratio	Atomic mass	Relative number of atoms	Simplest ratio
C	9	12	9/12 = 0.75	0.75/0.25 = 3
H	1	1	1/1 = 1	1/0.25 = 4
N	3.5	14	3.5/14 = 0.25	0.25/0.25 = 1

Empirical formula = C₃H₄N
Empirical formula mass = (3 × 12) + (4 × 1) + 14 = 54
Thus, Molecular formula of the compound = (Empirical formula) x n
= (C₃H₄N)₂= C₆H₈N₂

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In an organic compound, the ratio of masses of C, H and N are 9:1:3.5 and molecular mass is 108. What will be the empirical formula and molecular formula of the compound.

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