In an oxidation-reduction, MnO_(4)^(-) ion is converted to Mn^(2+), what is the number of equivalents of KMnO_(4) (mol. Wt.=158) present in 250 mL of 0.04 M KMnO_(4) solution ?

In an oxidation-reduction, MnO_(4)^(-) ion is converted to Mn^(2+), wh

1.	In an oxidation-reduction, MnO_(4)^(-) ion is converted to Mn^(2+), what is the number of equivalents of KMnO_(4) (mol. Wt.=158) present in 250 mL of 0.04 M KMnO_(4) solution ?
Answer» 0.02 0.05 0.04 0.07 Solution :In redox-reaction : `8H^(+)+MnO_(4)^(-)+5e^(-) to Mn^(2+)+4H_(2)O` CHANGE in oxidation state of `MnO_(4)^(-) =(+7)-(+2)=+5` `therefore N_(KMnO_(4))=M_(KMnO_(4))XX5` `=0.04xx5=0.20` Number of equivalents `=(NV)/(1000)=(0.2xx250)/(1000)=0.05`