In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- and 2(1 - ) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been

In an R-L circuit excited by a battery of voltage E, the current and v

1.	In an R-L circuit excited by a battery of voltage E, the current and voltage across resistor are 1- and 2(1 - ) respectively. If there were an initial current of 2 A in the inductance, the voltage across resistance would have been
Answer» From the given data R = 2&ohm;, L = 2H and E = 2V. Because of initial current of 2A, i(t) = 1 - e-t + 2e-t = 1 + e-t. Therefore, VR = 2(1 + e-t).