InterviewSolution
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InterviewSolution
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In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t` `i=I_(0) sin (omegat-phi)` The average power in the circuit over one cycle of `AC` isA. `(E_(0)I_(0))/(2)`B. `(E_(0)I_(0))/(2)sinphi`C. `(E_(0)I_(0))/(2)cos phi`D. `E_(0)I_(0)` |
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Answer» Correct Answer - C Power= rate of work done in one complete cycle. or `P_(av)=(W)/(T)` or `P_(av)=((E_(0)I_(0)cosphi)T//2)/(T)` or `P_(av)=(E_(0)I_(0)cosphi)/(2)` where `cosphi` is called the power factor of an AC circuit. |
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