In aqueous solution of Al_(2)(SO_(4))_(3)concentration ofAl^(+3) is 1.8 M then what is the concentration of SO_(4)^(-2) ?

In aqueous solution of Al_(2)(SO_(4))_(3)concentration ofAl^(+3) is 1.

1.	In aqueous solution of Al_(2)(SO_(4))_(3)concentration ofAl^(+3) is 1.8 M then what is the concentration of SO_(4)^(-2) ?
Answer» Solution :`Al_(2)(SO_(4))_(3) RARR 2Al^(+3)+3SO_(4)^(-2)` `2Al^(+3) = 1.8` `Al^(+3) = (1.8)/(2) = 0.9` `SO_(4)^(-2) : 3 xx 0.9` `=2.7M`