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In balancing the half reaction `CN^(ө)rarrCNO^(ө)`(skeltan) The number of electrons that must be added is |
Answer» Correct Answer - D `CN^(-) to CNO^(-)` Oxidation number of nitrogen in `CN^(-)` `4+x = -1` and in `CNO^(-) 4 + x-2 =-1` `x=-5 , x=-3` `CN^(-)` is thus oxidised by losing two electrons. |
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