In BF_(3), the B-F bond length is 1.30Å, when BF_(3) is allowed to be treated with mMe_(3)N, it forms an adduct, Me_(3)N to BF_(3), the bond length of B-F in the adduct is

In BF_(3), the B-F bond length is 1.30Å, when BF_(3) is allowed to be

1.	In BF_(3), the B-F bond length is 1.30Å, when BF_(3) is allowed to be treated with mMe_(3)N, it forms an adduct, Me_(3)N to BF_(3), the bond length of B-F in the adduct is
Answer» greaterthan 1.30 Å smaller than 1.30Å equal to 1.30Å none of these Solution :In `BF_(3)`, there is back bonding in between fluorine and BORON due to presence of p-orbital in boron. , back bonding imparts double bond CHARACTERISTICS. As `BF_(3)` forms adduct, the backk bonding is not LONGER PRESENT and thus double bond cahracteristic DISAPPEARS. hence, bond becomes a bit longer than earlier (1.30Å).