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In Bohr's model of hydrogen atom, the period of revolution of an electron in the 1st orbit to that in the 2nd orbit are in the ratio |
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Answer» `1 : 2` `:. (T_(1))/(T_(2)) = (2pi r_(1))/(v_(1)) xx (v_(2))/(2pi r_(2))= (r_(1))/(r_(2)) .(v_(2))/(v_(1))` But `r_(n) = r_(1) n^(2), " i.e., " r_(2) = r_(1) xx 2^(2) = 4r_(1)` or `r_(1)//r_(2) = 1//4` and `v_(n) = v_(1)//n, " i.e., " v_(2) = v_(1)//2 or v_(2)//v_(1) = 1//2` Hence, `(T_(1))/(T_(2)) = (1)/(4) xx (1)/(2)= (1)/(8), " i.e.," T_(1) : T_(2) = 1 : 8` |
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