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| 1. |
In CaF_(2) " Crystal ,Ca^(2+)ions are present in FCC arrangement. Calculate the number of F^(-)ions in the unit cell. |
| Answer» Solution :No. of ` Ca^(2+)` IONS PER unit cell = `8xx 1/8 + 6 xx 1/2 = 4` HENCE, no of `F^(-)`ions per unit cell =` 2xx4 =8` | |