In `CaF_(2)` " Crystal , ` Ca^(2+)` ions are present in FCC arrangement. Calculate the number of `F^(-)` ions in the unit cell.

In `CaF_(2)` " Crystal , ` Ca^(2+)` ions are present in FCC arrangemen

1.	In `CaF_(2)` " Crystal , ` Ca^(2+)` ions are present in FCC arrangement. Calculate the number of `F^(-)` ions in the unit cell.
Answer» No. of ` Ca^(2+)` ions per unit cell = `8xx 1/8 + 6 xx 1/2 = 4` Hence, no of `F^(-)` ions per unit cell =` 2xx4 =8`

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In `CaF_(2)` " Crystal , ` Ca^(2+)` ions are present in FCC arrangement. Calculate the number of `F^(-)` ions in the unit cell.

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