1.

In `CaF_2` crystal, `Ca^(2+)` ions are present in FCC arrangment . Calculate the number of `F^-` ions in the unit cell.

Answer» No. of `Ca^(2+)` ions per unit cell =`8xx1/8+6xx1/2=4`. Hence, no. of `F^-` ions per unit cell = 2 x 4 =8


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