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In car lift compressed air exerts a force F_1 on a small piston having a radius of 5 cm. This pressure is transmitted to a second piston of radius 15 cm. If the mass of the car to be lifted is 1350 kg, what is F_1 ? What is the pressure necessary to ac complish this task ? |
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Answer» SOLUTION :`(F_(1))/(A_(1))=(F_(2))/(A_(2))` `F_(1)=F_(2)(A_(1))/(A_(2)) = F_(2)((pir_(1)^(2))/(pir_(2)^(2)))` `F_(1)= 1350xx9.8((5XX10^(-2))/(15xx10^(2)))^(2)` =1470 N. |
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