In carious method 0.12g AgBr obtained from 0.15g organic compound. Find out the percentage of AgBr in compound. (Ag= 108, Br =80)

In carious method 0.12g AgBr obtained from 0.15g organic compound. Fin

1.	In carious method 0.12g AgBr obtained from 0.15g organic compound. Find out the percentage of AgBr in compound. (Ag= 108, Br =80)
Answer» Solution :`underset(80g)(BR) RARR underset(188g)(AGBR)` Thus, 188g AgBr CONTAIN 80gm BROMINE. So, 0.120g AgBr contain, Bromine `= (80 xx 0.12)/(188)` % `Br = (80)/(188) xx (0.12)/(0.15) xx 100= 34.04%`