1.

In Carium method of estimation of halgoen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?

Answer»

0.6808<BR>0.3504
`42.1%`
0.5

Solution :Molar mass of `AgBr=108+80=188" g "mol^(-1)` LTBR Percentage of `Br_(2)=(80)/(188)XX(0.12)/(0.15)xx100=34.04%`


Discussion

No Comment Found