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In Carius method of estimation of halogen, 0.15 g of an organic compound gave 0.12g of AgBr. Find out the percentage of bromine in the compound (Ag = 108, Br= 80) |
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Answer» Solution :molar MASS of AgBr `= 108 + 80 = 188g mol^(-1)` <BR> `underset(80g)(Br) + Ag rarr underset(188g)(AgBr)` 188g AgBr CONTAINS 80g Br `:.` 0.12g AgBr contains, mass of `Br = (0.12g xx 80)/(188)` |
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