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In Carius method of estimation of halogens `250 mg` of an organic compound gave `141 mg` of `AgBr`. The percentage of bromine in the compound is (atomic mass `Ag = 108, Br = 80`)A. 24B. 36C. 48D. 60 |
Answer» Correct Answer - A `% X = ("Atomic mass of Br")/("Molecular mass of AgBr") xx ("Wt. of AgBr")/("Wt. of organic Bromide") xx 100` Thus `% Br = (80)/(188) xx (141)/(250) xx 100 = 24` |
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