In case of beats, produced by the superposition of two waves of equal amplitudes, if maximum intensity is x times the intensity of superposing wave then x = ……..

In case of beats, produced by the superposition of two waves of equal

1.	In case of beats, produced by the superposition of two waves of equal amplitudes, if maximum intensity is x times the intensity of superposing wave then x = ……..
Answer» Solution :AMPLITUDE of resultant wave in beats is, `A. =2A cos {((omega _(1) - omega _(2))/(2)) t }` `IMPLIES (A.) _(max) = 2A` `(because cos {( (omega _(1) - omega _(2))/(2) )t }` has maximum VALUE equal to 1) Now, `I _(max) prop (2A) ^(2)` Also we knwo that `I prop A ^(2)` `THEREFORE (I _(max))/(I) = (4A ^(2))/(A ^(2)) =4 ""...(1)` But, as per the statement `I _(max)=xI,` `therefore (I _(max))/(I) =x""...(2)` From equations (1) and (2),` x =4`