1.

In case of measurement of K. E, if error in measurement of mass is 2% and percentage error in velocity is 3%, the maximum error in measurement of 'KE' is.

Answer»
K.E. = 1/2 mv²
error in K.E. is
error in m + 2(error in v)
--> 2% + 2×3%
    = 8%


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